1
Folks I’m having trouble with changing an integer number starting with zero.
$agencia = 0736;
$conta = 999999;
$agencia = intval($agencia);
$conta = intval($conta);
echo($agencia); //resultado 478
Even without the intval was giving the same problem. However its putting in place of zero the number 1 for example. Will print correctly(1736). ::PHP version 7.0::
2
You can use the sprintf
sprintf('%08d', 1234567);
output: 012345678
8d is the amount of digits you want
1
Numbers started with zero, since valid, are interpreted based on 8 (octal), ie 02345674 was interpreted based on 8 and its representation based on 10 is 641980.
The warning manual on this on the page about integers
That one website does base 8 x base 10 conversions
if you do so I believe it will work (int)$agencia;
It did not work because this value I send to a class, and within the class already arrives converted as well. Luckily, in the link manual you passed, there’s a five-year commentary on a guy with the same problem. And the solution is ridiculous for a robust language like PHP.
puts here the solution to help the crowd then! want to edit my answer or create another is at will!
I put as an answer. Thanks!
1
@Lodi thanks for the help, in the comments of the manual I found this "solution".
$agencia = "0736" + 0;
In this way the decimal Octa is canceled and passes the value without the zero: 736; But then you just pick it up and put it back in with the function:
str_pad($agencia, 4 , '0' , STR_PAD_LEFT);
That completes left character quantities with zero.
Thanks for the help!
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Why not treat it as string? I believe it will solve your problem!
– Lodi
I tried, but as I pass the information to a class, when I rescue is already changed the value.
– Glenys Mitchell