Error summing each row of a 5x3 matrix

Question

Hello, I’m having a problem adding up each of the lines of my matrix and storing in a vector

my code is like this:

#include <stdio.h>
int conta(int * matriz[5][3], int * vet)
{
for (int i = 0 ; i<5; i++)
    {
        for (int j = 0; j<3;j++)
        {
            matriz [i][j] = i+j;

            vet[i] += matriz[i][j];
        }
    }
}

void imprimir(int * matriz[5][3], int * vet)
{
for (int i = 0 ; i<5; i++)
    {
        for (int j = 0; j<3;j++)
        {
            printf("%d",matriz [i][j]);
        }
        printf("\n");
    }

    for (int i = 0; i < 5; ++i)
    {
        printf("soma linha %d : %d \n", i , vet[i] );
    }
}
void main()
{
int matriz [5][3];
int vet[5] = {0};

conta(matriz,vet);
imprimir(matriz,vet);
}

for some reason he returns:

soma linha 0 : 6
soma linha 1 : 27
soma linha 2 : 48
soma linha 3 : 69
soma linha 4 : 90

and not :

soma linha 0 : 3
soma linha 1 : 6
soma linha 2 : 9
soma linha 3 : 12
soma linha 4 : 15

that should be your answer.

someone could help me?

Answer 1

The problem is in the parameters you have in the functions that are incorrect:

int conta(int * matriz[5][3], int * vet)
//            ^-- aqui

void imprimir(int * matriz[5][3], int * vet)
//                ^-- e aqui

The way it is, the functions get pointers to two-dimensional matrices, which is not what you pass on main. In addition the function conta has the type of return as int but returns no value. The logic itself of the sum is correct, as well as its assignment in the matrix.

Fixed the problems I pointed out stay like this:

void conta(int matriz[5][3], int * vet){
    // ...
}

void imprimir(int matriz[5][3], int * vet){
    // ...
}

Watch it work on Ideone

Answer 2

I believe in your role int conta, vet[i] needs to be incremented by i + j.

The complete function stays this way:

int conta(int * matriz[5][3], int *vet)
{
    for (int i = 0 ; i<5; i++)
    {
        for (int j = 0; j<3;j++)
        {
            matriz [i][j] = i+j;
            vet[i] += i+j;
        }
    }
}