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I wonder why at the time I run the algorithm, the line that asks to type the student’s name is printed on the screen 2 times.
Scanner input = new Scanner(System.in);
System.out.println("Quando o tamanho do conjunto de alunos");
int tamanho = input.nextInt();
String[] alunos = new String[tamanho];
for(int i = 0; i < tamanho; i++)
{
System.out.println("Digite o nome do aluno");
alunos[i] = input.nextLine();
}
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If you are answering the first question with 1, is because your loop rotates once to zero, and again to one. You need to use < instead of <=:
for(int i = 0; i < TAMANHO; i++)
And for each student, instead of picking up what was typed you’re picking up the rest of the previous line. Use next() instead of nextLine():
alunos[i] = input.next();
And why not create a list of the size you need?
String[] alunos = new String[TAMANHO];
It would also be recommended not to use TAMANHO so in high-box, it looks like a constant. It would be better to use tamanho.
Thanks solved! : D could give me a brief explanation about this nextLine difference to next?
@Ygorramos newtLine moves an internal Scanner cursor to the end of the line, and returns what was before it. next asks for a string and accepts when you enter.
@Ygorramos does not check "solved" on the question, just click the green V on the side of the answer to mark as accepted, the system already treats the question as solved.
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