Regex to pick word between two words or "/"

Question

Someone can help me, I would just take the word between resourceGroups and providers and assign to a variable in javascript.

/9c2a1079-35f0-4298-9eb3-7f63903f2ae1/resourceGroups/pegarEssaPalavra/providers/

Answer 1

You can try something like:

var caminho = "/9c2a1079-35f0-4298-9eb3-7f63903f2ae1/resourceGroups/perarEssaPalavra/providers/";
var separado = path.split('/');
var palavra = split[split.indexOf("resourceGroups") + 1];

The word you search will be in the variable palavra.

However, the way I did, obligatorily, the word you are looking for should always be after the word resourceGroups in his path.

That’s because with the split, I set your way through / and then search for the index on which the word resourceGroups is and add 1 more, resulting in the word you search for.

Answer 2

You can use a regex with .split() then convert the array to string with .join():

var string = "/9c2a1079-35f0-4298-9eb3-7f63903f2ae1/resourceGroups/perarEssaPalavra/providers/";
var resultado = string.split(/.*resourceGroups\/|\/providers\//).join('');

console.log(resultado);

Explanation:

A regex .*resourceGroups\/|\/providers\/ will break the string into everything that comes before resourceGroups/ or from /providers/, isolating the word perarEssaPalavra. But the resulting array split will have empty values:

["", "perarEssaPalavra", ""]

With .join('') i convert the array to string ignoring what is empty, resulting in perarEssaPalavra.

Using indexOf() with substring():

Another form without the use of regular expressions is the simple .indexOf() within a .substring():

var string = "/9c2a1079-35f0-4298-9eb3-7f63903f2ae1/resourceGroups/perarEssaPalavra/providers/";
var resultado = string.substring(string.indexOf("resourceGroups/")+15, string.indexOf("/providers"));

console.log(resultado);

Like the string resourceGroups/ has fixed size, just take its position in the string and add +15 (for the length of the string) to the position of the string /providers.

Answer 3

That regex /\/resourceGroups\/(.*)\/providers\// will take what is between /resourceGroups/ and /providers/ by means of a group.

Working

let texto = `/9c2a1079-35f0-4298-9eb3-7f63903f2ae1/resourceGroups/pegarEssaPalavra/providers/`

const expressao = /\/resourceGroups\/(.*)\/providers\//

console.log(texto.match(expressao)[1]);

Answer 4

A regex for this can be as follows:

.*\/([^/]+)\/[^/]+

In this case it will always take the penultimate group between the bars, if add 'test/' at the end, the expression will return 'providers'.

Javascript:

const regex = /.*\/([^/]+)\/[^/]+/;
const str = `/9c2a1079-35f0-4298-9eb3-7f63903f2ae1/resourceGroups/cte/pegarEssaPalavra/providers`;
let m;

if ((m = regex.exec(str)) !== null) {
    // The result can be accessed through the `m`-variable.
    m.forEach((match, groupIndex) => {
        console.log(`Found match, group ${groupIndex}: ${match}`);
    });
}

See the example here: https://regex101.com/r/v60aQS/1