Set which value will be stored in a PHP variable to be saved to the Database

Question

I have an HTML page where the user selects the information he needs and stores it in the database when he completes the operation. It is a small form in which there are practically only check boxes, except a single text box. In one of the check-boxes (problem type), when the user clicks on the "Machines" option, another select appears, in the case of machines. And if the user chooses the "Other" option, then it will open the only text box on the page. Follow the current code.

HTML:

<select name="tipobroblema" id="tipoproblema">
    <option value="">- Tipo Problema -</option>
    <option value="maquina">Maquina</option>
    <option value="vazamento">Banheiro</option>
    <option value="arcondicionado">Ar Condicionado</option>
    <option value="outro">Outro</option>
</select>

<div id="divOutro" style="display:none;"><input type="text" name="outro" /></div>

<select id="divMaquina" name="maquina" style="display:none;">
    <option value="">- Maquinas -</option>
    <option value="maquina1">Maquinas1</option>
    <option value="maquina2">Maquinas2</option>
    <option value="maquina3">Maquinas3</option>
    <option value="maquina4">Maquinas4</option>
</select>

Script:

<script>                        
    $('#tipoproblema').change(function(){
    if(this.value == 'maquina') {
        $('#divMaquina').css('display', '');
        $('#divOutro').css('display', 'none');}
    else if(this.value == 'outro') {
        $('#divMaquina').css('display', 'none');
        $('#divOutro').css('display', '');}
    else {
        $('#divMaquina').css('display', 'none');
        $('#divOutro').css('display', 'none');}
   });
</script>

When the user clicks on "Generate" to record in the database, the data will go to a PHP page, thus using the POST to get the data that was informed by the user. Before adding the check-box and the "interactive" text (which appear depending on the selected option). I used only:

$problema = $_POST['tipoproblema'];

Thus, taking the value that the user selected and passing to a variable.

Since it was only one, there was no difficulty. He looked for the name of the field, in the case "typoproblema" took the selected value and stored it in the Database. Now there are three possibilities. That is, the way it was, it would continue to store the types of problems in the bank (such as the value "other" and "machines" instead of saving the selected machine or the text typed by the user). I don’t know much about PHP so far, I would really appreciate your collaboration.

Answer 1

When you send the form to PHP it will create the keys of the array $_POST according to the names of <input>s:

$tipoproblema=$_POST['tipoproblema'];
$outro=$_POST['outro'];
$maquina=$_POST['maquina'];

So you can capture the values of <input>s.