Help with Ajax does not send data to the database

Question

I’m trying to submit a form to my database. Ajax says that the user’s registration was carried out successfully but when I go to look in the database there is nothing there.

My Form.

<form class="form3" method="POST" enctype="multipart/form-data">
    <div id="ressult"></div>

    <p>Nome completo</p>
    <input type="text" name="Nome_us" placeholder="Nome completo *">

    <p>Nome de usuário</p>
    <input type="text" name="Nick_us" placeholder="Nick da conta *">

    <p>E-mail</p>
    <input type="text" name="Email_us" placeholder="Informe seu E-mail *">

    <p>Senha</p>
    <input type="password" name="Senha_us" placeholder="Informe a sua senha *">

    <input type="hidden" name="Imagem_us" value="/images-profile/Profile_img_00_TSN.png">
    <input type="submit" id="Bot_Cria_login" name="Cadastrar_us" value="Criar conta">
</form>

My ajax.

<script>
    $(function(){
        $('.form3').submit(function(event){
            event.preventDefault();
            var formDados = $('.form3');

            $.ajax({
                location:'/arquivos/conta_usuario.php',
                type:'POST',
                data:formDados,
                cache:false,
                contentType:false,
                processData:false,
                success:function(data){
                    $('#ressult').html(data);
                    alert('Cadastrado com sucesso!');
                },
                dataType:'html'
            });
            return false;
        });
    });
</script>

My php where I want to send the data I filled.

<?php
    require_once('conex.php');

    if(isset($_POST['Cadastrar_us'])){
        $Nome_user      = $_POST['Nome_us'];
        $Nick_user      = $_POST['Nick_us'];
        $Email_user = $_POST['Email_us'];
        $Senha_user = $_POST['Senha1_us'];
        $Imagem_user    = $_POST['Imagem_us'];

        if($Nome_user == ""){
            echo 'Preencha o campo Nome corretamente.';
        }
        else{
            $SQL_Cadastro = mysqli_query($conex,"INSERT INTO Usuarios_login_s_n (Nome_us_sn, Nick_us_sn, Email_us_sn, Senha_us_sn, Foto_us_sn) VALUES ('$Nome_user', '$Nick_user', '$Email_user', '$Senha_user', '$Imagem_user')");
        }
    }
    else{

    }
?>

Answer 1

In the row below, you are sent the form HTML , and not the data:

var formDados = $('.form3');

To store form data to variable, use the method .serialize():

var formDados = $('.form3').serialize();

The contentType is also wrong. Remove it that will be sent from the default type. Also change the location of Ajax by url.

The fact that you are receiving the alert does not mean that the data has been received, it just means that something is returning without errors.

Your Ajax will look like this:

$(function(){
  $('.form3').submit(function(event){
      event.preventDefault();
      var formDados = $('.form3').serialize();

      $.ajax({
          url:'/arquivos/conta_usuario.php',
          type:'POST',
          data:formDados,
          cache:false,
          processData:false,
          success:function(data){
              alert('Cadastrado com sucesso!');
          },
          dataType:'html'
      });
      return false;
  });
});