Identify the input URL of a Filter

Question

How do I identify by which URL a filter is being accessed?

My situation is as follows:

I have the class below:

@WebFilter(filterName = "FiltroLogado", urlPatterns = {"/alterar.jsp",
"/deletar.jsp", "/cadastrado.jsp", "/logado.jsp"})

public class FiltroLogado implements Filter{

@Override
public void init(FilterConfig filterConfig) throws ServletException {

}

@Override
public void doFilter(ServletRequest servletRequest, ServletResponse 
servletResponse, FilterChain filterChain) throws IOException, 
ServletException {

HttpSession session = ((HttpServletRequest) 
servletRequest).getSession();

if (session.getAttribute("usuario") == null){
    ((HttpServletResponse) servletResponse).sendRedirect("index.jsp");

}else
    if(){
    ((HttpServletResponse) servletResponse).sendRedirect("alterar.jsp");

}

}

I want to know by which URL the filter is being accessed to forward to the specific location of the link, for example by accessing the filter through the URL "/alterar.jsp", I want him to go to "/alterado.jsp".

Answer 1

@Override
public void doFilter(ServletRequest servletRequest, ServletResponse 
servletResponse, FilterChain filterChain) throws IOException, 
ServletException {
    HttpServletRequest request = (FAZER CAST) servletRequest;
       if ( request instanceof HttpServletRequest ) {
             String url = ((HttpServletRequest)request).getRequestURL().toString();
             String queryString = ((HttpServletRequest)request).getQueryString();
            }

           System.out.println( url + "?" + queryString);
    }

}

you can make a if to know which page and redirect.

Answer 2

I used the method getServletPath to verify by which of the Urls the request had entered.