Regex: Open and close with the same character and allow more than one type

Question

It is possible to get a text between two characters that are equal, with the following conditions:

• The opening character shall be the same as the closing character.
• Allow more than one character type in opening/closing.

Simple example:

/("|')asdasd("|')/

Let me take "asdasd" and 'asdasd'

But he also takes "asdasd'

How to make when it is opened with ", allow to close only with "?

Answer 1

You can use \1 to ensure the use of the same character as in a capture group.

Thus, define some "limiters" at the beginning of the string, and at the end use \1 to make sure you have the same:

var testes = [
  '!abba!', '?abba?', '"ab ba"', "'abba'", 'xabbax', '!eu vou falhar?'
];

function filtro(str) {
  var match = str.match(/([!?'"x])(.*)(\1)/);
  if (!match) return '';
  return match[2];
}

console.log(testes.map(filtro));

In cases where you want to use pairs of symbols to open and close a text region, such as {}, () or <> this could be done:

const testes = [
  '(abba)', '!eu vou falhar?', '{abba}', '<A>'
];
const separadores = ['{}', '\\(\\)', '<>'].map(char => {
  const abertura = char.slice(0, char.length / 2);
  const fecho = char.slice(char.length / 2);
  return `(${abertura})([^${fecho}]+)(${fecho})`
}).join('|');
console.log(separadores)
const regex = new RegExp(separadores);

function filtro(str) {

  var match = str.match(regex);
  match = match && match.filter(Boolean);
  if (!match) return '';
  return match[2];
}

console.log(testes.map(filtro));

Answer 2

See if this is it :

/\(asdasd\)|{asdasd}/g

Explanation in English