Regex in javascript for partial match in URL

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I need to write a javascript regex that contains a specific piece of URL, but I’m not able to, mainly because it’s a url with "/".

Example: Any "like" or partial match to "www.url.com/foo"

www.url.com/foo/bar/send/123   - true
www.url.com/foo/doe/get/123    - true
www.url.co/foo/doe/get/123     - false
http://www.url.com/foo/get/123 - true
http://www.url.co/foo/doe/123  - false

Any idea how to make a "generic" regex for any other urls as well?

javascript regex

  • The url.com it’s fixed whatever comes next can be anything?

  • Have you tried declaring the regular expression Regexp? var re1 = new Regexp("abc");

3 answers

3


You can use the .test of Regexp:

/\w+\.com(\/[\/\w]*)?$/.test(url);

Remembering to escape from "/".

var url = "www.url.com/foo/bar/send/123"; 
var res = /\w+\.com(\/[\/\w]*)?$/.test(url);

console.log(url, ' -> ', res);

var url = "www.url.co/foo/bar/send/123"; 
var res = /\w+\.com(\/[\/\w]*)?$/.test(url);

console.log(url, ' -> ', res);

  • I believe it worked, thank you! I was stuck in the question of using "/" to signal bars.

  • @Jhonathan with this answer if I have the following URL: qu@alq3ercoisaAqu!->.url.com/foo/bar/send/123 the result will still be TRUE

  • 1

    This code limits you to only one specific domain and not to any domain.

  • @Thiagooliveira truth, well noted.

1

You can use this regex: /(http:\/\/)?www\.\w+\.com.+/g as follows:

var regExp = /(http:\/\/)?www\.\w+\.com.+/g;
var url = 'url-aqui';
var resultado = regExp.test(url); //retorna true ou false

So you take the URL o http:// which may or may not exist, the www, any text you are after and end the domain with .com.

  • And if it’s https, or ftp or file?

  • Then you can modify the expression as follows: /(http:\/\/)?(https:\/\/)?(ftp:\/\/)?(file:\/\/)?(www\.)?\w+\.com.+/g. So you can include any protocol you want to check, and also consider Urls that do not contain the www.

  • With this answer if you have anything before http, it will also give TRUE, would have to add the ^ after the / At the beginning of Pattern to stay straight.

  • You can get that look on your face: /^((http|https|ftp|file):\/\/)?(www\.)?\w+\.com.+$/g.

0

The best way to work with url is to put it in a string and use Regexp, as it automatically escapes the bars, so you can write your test url normally.

var url = "www.url.com/foo/bar/";
r = new RegExp(url);
console.log(r);

From what I understand what you want to check is if the domain is correct for this you can do so.

var dominio = 'www.url.com';
var r = new RegExp(dominio);

console.log(r)

var testes = [
  'www.url.com/foo/bar/send/123',
  'www.url.com/foo/doe/get/123',
  'www.url.co/foo/doe/get/123',
  'http://www.url.com/foo/get/123',
  'http://www.url.co/foo/doe/123',
]

for(var i in testes){
  var url = testes[i];
  console.log(url, url.match(r)!=null);
}

And so to check the url with foo just change to var dominio = 'www.url.com/foo'

  • Beware of the point in regex, this regex can marry wwwwurl.com with no problem.

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