Button running one function in js and another in php

Question

Good afternoon guys, I’m having a doubt would have as soon as I clicked on the button it called a function in js and another in php?

I have a problem I want a variable in case $name receives the value you type in an input and when you click on the button do the check with db and return on the same page the results,

<script type="text/javascript">
  	function fnome() {
  	$nome = document.getElementById('nome').value;
  }
  	
  	
</script>

<button onclick="fnome()">Pega</button>

 <?php 

		
		$sql = mysql_query("SELECT * FROM pedidos WHERE nome LIKE '%".$nome."%'");
		$row = mysql_num_rows($sql);
		if ($row > 0) {
			while ( $linha = mysql_fetch_array($sql)){
				$id = $linha['id'];
				$nome = $linha['nome'];
				$pedido = $linha['pedido'];
				$valor = $linha['valor'];
				
				echo "<br><br>ID: ". @$id;
				echo "<br><strong>Nome: </strong>". @$nome;
				echo "<br>Pedido: ". @$pedido;
				echo "<br>Valor: ". @$valor	;
				
			}
		}
		else {
			echo "Desculpe nenhum pedido foi encontrado!";
		}
	
	 ?>

Answer 1

So Samuel, I think that the way you want it is not possible, because Javascript and PHP will try to run at the same time, the easiest to do is to do the verification you want via Javascript.

Allocate this PHP code to another file and call it via AJAX within Javascript after doing the verification you want, here’s a tutorial to help you with AJAX:

http://api.jquery.com/jquery.ajax/

The summary of what I recommend you to do is: Allocate the PHP function in another file, do it in index.html or index.something and call the PHP file via AJAX after you run the validation you want with JS.

If it is not clear, just warn :) Hugs!