Find 2 date attributes in a single element

Question

How can I find a particular attribute that contains another specific attribute? for example:

<a class="fc-draggable" data-belongs="3" data-target="2"></a>

I can select all elements that contain a certain attribute using:

$('*[data-belongs="3"]');

But how do I select all data-belongs='2' containing data-target='3'?

Answer 1

Try this:

$('*[data-belongs="2"][data-target="3"]');

Source: jQuery: Multiple attribute selector

Answer 2

You can use $('[data-belongs="2"][data-target="3"]'); as I mentioned in comment, so you search for elements with both attributes.

To select through the element attributes we can use the attribute selectors followed by each other.

To filter later we can use the .not() thus:

$('a[data-belongs]').not('[data-belongs="' + nr + '"][data-‌​target="' + nr + '"]‌​').hide();

Example: https://jsfiddle.net/k9h3kka3/