0
I have the following code:
<?php
if(isset($_FILES['files'])){
$errors = array();
foreach ($_FILES['files']['tmp_name'] as $key => $tmp_name){
$file_name = $key.$_FILES['files']['name'][$key];
$file_size = $_FILES['files']['size'][$key];
$file_tmp = $_FILES['files']['tmp_name'][$key];
$file_type = $_FILES['files']['type'][$key];
$file_parts = pathinfo($file_name);//Returns an associative array containing file information
$extensions = array("jpeg","jpg","png");//Allowed file
if($file_size > 2097152){
echo 'Tamanho do arquivo de ser menor que 2MB';
}else{
if(in_array ($file_parts['extension'],$extensions)){
//Rename file
$file_parts = ".".$file_parts['extension'];
$file_name = uniqid().$file_parts;
if(empty($errors)==true){
//Move the file to a specific folder
move_uploaded_file($file_tmp, "img/".$file_name);
}else{
print_r($errors);
}//if(empty($errors)==true){
}else{
echo'Extensão não permitida';
}//if(in_array ($file_parts['extension'],$extensions))
}//if($file_size > 2097152){
if(empty($errors)){
print_r("<pre>".$file_name."</pre>");
}//if(empty($errors))
}//foreach ($_FILES['files']['tmp_name'] as $key => $tmp_name)
}
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Upload</title>
</head>
<body>
<form action="" method="POST" enctype="multipart/form-data">
<input type="file" name="files[]" multiple>
<input type="submit" value="Enviar">
</form>
</body>
</html>
My question is, which is better, to create a table in the database for the images, so when I need these images in some form I do one to many interaction, or turn the array into a string?
Does it have another solution too?