Access multidimensional arrays of a php input

Question

I have several image arrays in the following format:

<input type="file" name="imagens[$id][]">

The $id is changed dynamically. How do I access to take some of the image data, the name for example, in php?

Updating:

Array
(
    [45] => Array
        (
            [0] => 1.jpg
            [1] => 2.jpg
            [2] => 
        )

    [44] => Array
        (
            [0] => 4.jpg
            [1] => 5.jpg
            [2] => 
        )

)

Solution: I was able to access it this way:

$_FILES['imagens']['name'][$id]

Answer 1

First note that in your array not the key name or tmp_name which is common when using $_FILES in PHP.

This way I know you must be using the wrong method to capture the form data. (You must be using $_POST).

Usually when you want to make one upload file(s), if used :

<form action="upload.php" enctype="multipart/form-data" method="post">
    <input type="file" name="imagens[$id][]">
</form>

Note that in the form this method="post", however in PHP you should capture it by $_FILES. What should generate an array like this :

Array
(
    [45] => Array
        (
            [0] => Array 
                (
                    [name] => 1.jpg
                    [type] => image/jpeg
                    [tmp_name] => /tmp/php/php6hst32
                    [size] => 98174
                )
            [1] => Array 
                (
                    [name] => 2.jpg
                    [type] => image/jpeg
                    [tmp_name] => /tmp/php/php6hst32
                    [size] => 98174
                )
        )

    [44] => Array
        (
            [0] =>  Array 
                (
                    [name] => 4.jpg
                    [type] => image/jpeg
                    [tmp_name] => /tmp/php/php6hst32
                    [size] => 98174
                )
        )
)

To manipulate your content you can use foreach:

foreach($_FILES as $id => $files){
    foreach($files as $k => $file){
        $name = $file['name'];
        $tmpName = $file['tmp_name'];

        printf("name : %s\n tmpName : %s", $name, $tmpName);
    }
}

Answer 2

Since you don’t know the value of the key, the ideal is to go through the array:

foreach($_FILES['imagens'] as $img){
   echo $img['tmp_name'];
}