5
In php, when I want to generate a array formatted, I use the function array_map.
Thus:
$numeros = range(1, 10);
array_map(function ($value) {
return sprintf('%04', $value);
}, $numeros);
Returns:
array('0001', '0002', '0003', '0004' ...);
Already in python, for that list range(1, 10) how could I do that same operation?
Is there some short and simple way to do this (same or better than in PHP)?
5
Yes.
numeros = list(range(1, 10))
resultado = [str(x).zfill(4) for x in numeros]
3
Only as a complement to the @Ciganomorrizonmender:
This operation, in Python, is called List Comprehensions.
It can be used to build the lists in a very simple way.
If the goal is only to create the formatted list, without the need to have the non-formatted value in a variable, we can simply already make the following statement directly, without creating a variable before.
senhores = ['Senhor %s' % (nome) for nome in ['wallace', 'cigano', 'bigown']]
Return is:
['Senhor wallace', 'Senhor cigano', 'Senhor bigwon']
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The guy put a "Yes" just not to get just code. I liked this function
zfill. Good to know there’s such a thing inpython, without having to keep creating– Wallace Maxters
The solution is correct, but zfill is rarely used. In general the method is used
formatof the strings, which has a whole mini-formatting language and can do a lot more than just fill zeros. With format, it would be: `result = ["{:04d}". format(x) for x in range(1,10)]– jsbueno
Alias - in this case there is no need to use
list(range(..))- the behavior offoris identical for both the Python 2 range and the Python 3 range– jsbueno
@jsbueno, our pythonico boy
– Wallace Maxters