Relate 2 objects to a single reference/key

Question

I have a while(true) which accepts multiple connections (Socket and Serversocket). Each connection is passed to a Processing object that handles your reading/writing of data. This Processing is passed to a Thread so you can accept connections and read/write simultaneously.

I was wondering if there’s any way to save these two objects (Treatment and Thread) so that they have a key of identification, for when I need to close them, call this key, receive the 2 objects and close them individually.

Answer 1

You can make a tuple class (for 2 elements). As described here: https://stackoverflow.com/a/12328838/2236741

With this class you even have the hash calculation taking into account the two objects. Modify it to your reality if necessary.

In this case it would look like this:

Map<Integer, Tuple<Tratamento,Thread>> objs = new HashMap<Integer, Tuple<Tratamento,Thread>>();

You will probably have to have some kind of object that stores keys that have not yet been closed.

If more than one thread goes to Hashmap, then you need to use a thread-safe version called Concurrenthashmap.

Update - Example of use

Below is an example of how to use it. Note that I used Integer, String instead of Thread and Treatment.

    HashMap<Integer, Tuple<Integer,String>> objs = new HashMap<Integer, Tuple<Integer, String>>();
    objs.put(10,new Tuple<Integer, String>(150,"ABC"));
    objs.put(11,new Tuple<Integer, String>(300,"DEF"));

    Tuple<Integer,String> tuple = objs.get(10);

    System.out.println(tuple.x);
    System.out.println(tuple.y);


    tuple = objs.get(11);

    System.out.println(tuple.x);
    System.out.println(tuple.y);

If you want, just change the attributes of the Tuple class from x and y to Treatment and Thread. However, your class will no longer be generic. If you only need it for this part of your code, switch to make it clear.