Add typed values without using array

Question

Prepare a program that asks the user to enter 10 values, add this results and present on the screen.

I could only do it with one array whole.

#include <stdio.h>
#include <stdlib.h>

int main()
{
  int i, soma;
  soma = 0;
  int num[10];
  printf("Digite 10 numeros para somar:\n");
  for(i= 0; i<10; i++) {
    printf("Digite a %d nota: ", i+1);
    scanf("%d", &num[i]);
    soma +=num[i];
  }
  printf("\nSoma = %d : ", soma);

  system("pause");
   return 0;
}

How do I add the 10 read values without using array???

Answer 1

The use of array was just getting in the way, just use a normal variable instead of a array, after all it had no function in the algorithm.

#include <stdio.h>

int main() {
    int soma = 0;
    printf("Digite 10 numeros para somar:\n");
    for (int i = 0; i < 10; i++) {
        int num;
        printf("Digite a %d nota: ", i + 1);
        scanf("%d", &num);
        soma += num;
    }
    printf("\nSoma = %d : ", soma);
}

Behold working in the ideone. And in the repl it.. Also put on the Github for future reference.