1
Is there a way to add, not manually, an indexed array? For example:
$arrayNomeBDs[0] = array (
"nome_tabela" => "TabelaDeNome1",
"db-tb-name" => "table_name_bd1"
);
$arrayNomeBDs[1] = array (
"nome_tabela" => "TabelaDeNome1",
"db-table-name" => "table_name_bd2"
);
If I put in the next iteration as index = 3
, make a mistake
$arrayNomeBDs[3] = array (
"nome_tabela" => "TabelaDeNome1",
"db-tb-name" => "table_name_bd2"
);
This is my for
to traverse:
will give error if I put index = 3 if I follow the previous example:
for($i = 0; $i<sizeof($arrayBDs);$i++){
var_dump($arrayBDs[$i]['nome_tabela']);
if($arrayBDs[$i]['nome_tabela'] === $BD_Escolhido){
return $arrayBDs[$i]['db-tb-name'];
}
}
In the future it will be difficult to remove a bank from the array and manually put the index in order all over again, as I have 40 banks to create (all the time a new bank comes in or one or more is removed), so later on it will be difficult to do maintenance.
From what I understand you’ll be removing and adding items, right? If so, have you ever thought of using a chained list instead of an array?
– Armando K.
not thought to use, this array contains several tables that will change in time to time, on the front the person chooses the name of the database (put a generic value), after I send this name pro php, there I look for that name and return the table name of the database. I did this so user did not have access to database name.
– chocolatemontana
From the description of your problem I think you could use a list instead of the array, it will solve the main problem you described: "in the future it will be difficult to remove a database from the array and manually put the index in order all over again". With a list you don’t have to worry about reordering the index, it does this automatically.
– Armando K.
how do I do this in php? a list of objects? rsrs
– chocolatemontana