Sequential Static List

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Guys look at this following code :

lista is a struct

lista * crialista()
{
    lista *li;

    li = (lista *) malloc(sizeof(struct lista));

    if(li !=NULL)
    {
        li->qtd = 0 ;
    }
}

because it was allocated lista in li with malloc ? whereas li was declared as lista , that no longer gives access to members of my struct lista?

c c++
  • 1

    lista *li defines a pointer. But that pointer does not point anywhere defined! If you prefer a real object, you can do lista li which is a real object with uncirculated values; with a pointer you have to point it to a specific place (with malloc()) and then assign values to the elements.

1 answer

4


When did you declare lista *li you just said that you will get a pointer of type list. It would be the equivalent to say int *i. This last statement does not say that you have an entire variable, and you cannot store any value in i, because it is a pointer and not a conventional integer. The same goes for type lista. The pointer *li cannot have common values, but addresses, stored in it. Therefore it is necessary to allocate a space in memory, to save the information in your struct and then point to it with your pointer li.

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