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How do I make a Dialog appear when the script occurs correctly?
public function addDatabase($name, $collation) {
    // Checks whether all fields filled (Prevent future errors)
    if (!empty($name) AND !empty($collation)) {
        try {
            // If you want to change (Don't forget the ;)
            // http://dev.mysql.com/doc/refman/5.6/en/create-database.html
            $sql_query = 'CREATE DATABASE `'.$name.'` COLLATE `'.$collation.'`;';
            // Prepare the query to execute
            $query = $this->db->prepare($sql_query);
            // Execute the query
            $query->execute();
        } catch (PDOException $e) {
            exit ('DB ERROR: '. $e->getMessage());
        }
    } else {
        if (empty($name)) {
            echo '$name está vazio';
        }
        if (empty($collation)) {
            echo '$collation está vazio';
        }
    }
} 
CSS/JS of the dialog: http://materializecss.com/dialogs.html
" PHP that receives the AJAX call " This would be on which page? Inside the form ? EDIT: I’ll try to put it in the controller.php because it takes the model information
– misakie
EDIT: I noticed that it is returning successss and error. However no dialog is appearing in the index. Code completo http://www.codeshare.io/LZKq0
– misakie
You’re not sending anything through ajax, assign a
idto hisformand place these lines in your ajax just belowurl: ..,type: 'POST', data: $('#seuform').serialize().– Eduardo Silva
Code updated: More where do I put href and which link? http://www.codeshare.io/LZKq0
– misakie
You will need a php to receive the data from your form and instantiate the class
Controller, this is the php that needs to be placed in the parameterurl:of your js code, I’ll make an example here on my machine for you to have a complete view. 4 files will be used (index.php, Controller.php, Model.php and another.php file)– Eduardo Silva
Sorry for the delay, I ran out of computer. But, where is the example?
– misakie