Regex to get a dd/MM/yyyy date by ignoring characters in the middle?

Question

In this case I can have a string like

String data = "20/dsauh'03*/2021";

My idea was to do something like:

Pattern p = Pattern.compile("([0-9]{1,2}\\/[0-9]{1,2}\\/[0-9]{4})"); 
        
Matcher matcher = p.matcher(data);
        
if (matcher.find()) {
    result = matcher.group();
}

However, this regex I’m applying doesn’t ignore the characters in the middle of the String data I gave you as an example. I would like to know if you can apply a regex that captures a date in the dd/MM/yyyy format and still ignore if there are other characters in the middle?