-1
For example, if I have a dictionary like this:
{
x: { 1, 2, 3 },
y: { 2, 3, 4 },
z: { 1, 5, 6 }
}
How do I remove all occurrences of 2
?
-1
For example, if I have a dictionary like this:
{
x: { 1, 2, 3 },
y: { 2, 3, 4 },
z: { 1, 5, 6 }
}
How do I remove all occurrences of 2
?
0
Simply iterate through the sets, and remove the 2
of each.
dicionario = dict()
# Iniciando valores no dicionário
dicionario['x'] = set([1, 2, 3])
dicionario['y'] = set([2, 3, 4])
dicionario['z'] = set([1, 5, 6])
# Para cada conjunto...
for conjunto in dicionario.values():
# Remova o valor 2
conjunto.discard(2)
# Mostrar resultado
print(dicionario)
I used the method discard
to the detriment of remove
, for remove
throws error when the item does not belong to the set. Already the discard
does nothing, silently, which is the behavior we desire.
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