Grab information, open window and only release window when entering a password. Python

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I will simulate an attack on my company to identify the most vulnerable users to intensify training in order to avoid ransomware and type viruses.
I’m trying to create a little program. exe to take the computer information (machine name, user name, operating system and current date) and send by email. After that, I wanted to open a window with some repetitive messages to make it impossible for the user to continue working and only release with a password that T.I has. Can help me?

My current code is like this:

import platform
from datetime import datetime
import getpass
import ctypes

so = platform.system()

print ("Sistema Operacional:"+so)
print ("Nome da máquina:"+platform.node())
print ("Nome do usuário:"+getpass.getuser())


data_e_hora_atuais = datetime.now()
data_e_hora_em_texto = data_e_hora_atuais.strftime("%d/%m/%Y %H:%M")

print(data_e_hora_em_texto)


def Mbox(title, text, style):
    return ctypes.windll.user32.MessageBoxW(0, text, title, style)
Mbox('ATENÇÃO!!!!@@!!', 'VOCÊ BAIXOU O ARQUIVO, CERTO?', 3)
Mbox('ATENÇÃO!!!!@@!!', 'VOCÊ FOI INFECTADO :)', 0)
Mbox('ATENÇÃO!!!!@@!!', 'NÃO TENTE FAZER NADA SENÃO VAMOS ESPALHAR POR TODA REDE', 0)
Mbox('ATENÇÃO!!!!@@!!', 'CHAME ALGUÉM DO T.I PARA CONVERSAR COMIGO', 0)

n = 1

while n != 0:
    n = int(input('Digite a senha: '))
print('Liberado')
python
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1 answer

-3

Try this one: First check whether n != 0 and it’s not 123456:

Note: The T.I password you could put in a development variable file or something like...

n = 1

while n != 0 and n != 123456:
    n = int(input('Digite a senha: '))

    if n == 123456:
        print('Liberado')
    else:
        print('Senha incorreta')

123456 you can switch to the password you choose

  • 1

    Ata, I get what you want, you want to block the guy’s computer really... I don’t think we can help you with this... but there’s an excerpt of the code...

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