Dynamic pages through request

Question

I’m setting up a web application in a way that future maintenances will be well simplified.

So I started searching for dynamic pages, etc. Except in practice, I don’t even know how to start.

I wanted it to stay that way:

• header.php: header with side menu linking to other pages

• content.php: (I’ve already done )

• footer.php: (I’ve already done )

---

In my index.php, I call the css files, js, etc. And give a include in header, content, footer...

Slurry :

1. lib/

2. application/

3. controllers/

4. template/ header.php , content.php, footer.php

   • index php.

So far blz ...

In my header, in the menu, there are several links, but I didn’t want to have to create 15, 20 different pages. But yes, 1 single page with the content related to each link.

How do I do that?

---

I was thinking about how I could do it , along with the database , we test is almost all going well , but it is not displaying my content.

Just like I did :

I created a table (tblPaginas), placed in it the fields : id ,name , controller , Arg and ennable.

id name     controller arg  ennable
1  index                0     0

2  pagina1     pag      1     1

3  pagina2     pag      2     1

4  pagina3     pag      3     1

etc.

In my header , I put the following :

<?php       
    echo '
        <li>
                    <a href="javascript:;">
                    <i class="icon-basket"></i>
                    <span class="title">PAGINAS</span>
                    <span class="arrow "></span>
            </a>';

    echo ' <ul class="sub-menu">';

                $sql= ("SELECT * FROM tblPaginas where ennable = 1 and arg > '0' order by id ");
                $query = mysql_query($sql);
                while($row = mysql_fetch_array($query))
                {

                echo'                         
                    <li>
                            <a href="index.php?'.$row['controller'].'='.$row['arg'].'">
                            <text style="TEXT-TRANSFORM: uppercase;">'.$row['name'].' </text></a>
                    </li>' ;}

                    echo '</ul>';
                    echo '</li>';
?>

So , it displays my side menu , grabbing the 'name' (name of the page in the menu) and sending the controller and Arg through the URL .

On my content.php page, I tried to do the following :

<?php
$uri = $_GET['arg'];

    $var = $uri;
    switch ($var)
{
    case 1:
    include 'pag/geral.php';
    break;

    case 2:
    include 'pag/pagina2.php';
    break;

    case 3:
    echo "DEU CERTO O 3";
    break;
}

?>

But, he is not displaying the pages , is not working this code I made the page content.

I thought about doing so , because I can later try to make a control panel , and edit the pages by the bank.

Can you help me make this code work?