Compare two to two elements of a vector

Question

Good afternoon! I am studying python3 (I am very beginner), and I would like, given a vector, to compare the elements of this vector 2 to 2 to see if they are equal. for example: [2,3,4,4,5] 2 compares with 3, and we have that 2!=3 3 compares with 4, and we have that 3!=4 4 compares with 4, and we have that 4==4 4 compares with 5, and we have that 4!=5

What I thought was something like

for x in vetor2:
   if vetor2[x]==vetor2[x+1]:

Meanwhile, out of range... thank you!

Answer 1

One way to implement it would be:

vetor = [2,3,4,4,5]
for x in range(len(vetor)-1):
    if vetor[x]==vetor[x+1]:
        print('sim')
    else: 
        print('não')

For this code I used the functions len and range that are part Built-in Functions python.

Explaining the code

The function range will generate a sequence of immutable numbers up to a value.

When used with an integer type parameter, this function will generate numbers up to the value passed as parameter (in this case it will be the len(vetor)-1).

Already the function len returns the number of items of an object (object here can be: string, array, list, tuple or Dictionary, Python types)

Answer 2

Could do so:

for i in range(1, len(vetor2)):
    if vetor2[i]==vetor2[i-1]:
        print(vetor2[i])

That is, starting from 1 (the first position is zero) and comparing with the previous (i-1)

Or so, limiting to size at least 1 (len(vetor2)-1) and compared with the next without letting go of the limit and give the error of your question.

for x in range(len(vetor2)-1):
    if vetor2[x]==vetor2[x+1]:
        print(vetor2[x])