In if, when the user puts another state that is not specified, instead of entering Else, he enters if and continues the code normally

Question

The code is like this:

est = input('Qual estado reside atualmente? ')  
if est == 'São Paulo' or 'SP' or 'sao paulo' or 'São paulo':  
    email = input('Digite o seu e-mail: ')   
    tel = input('Digite o seu celular pessoal: ')  
    tel2 = input('Digite seu telefone comercial ou residencial: ')  
else:  
    print('Não atendemos na sua localidade!')  
    exit()  

Answer 1

You could write the if conditions the same way you wrote the first conditional. Follow the example:

if est == 'São Paulo' or  est == 'SP' or  est == 'sao paulo' or  est == 'São paulo': 

I am highlighting just the excerpt of if, how it could be rewritten in a way that can be evaluated correctly.

In his code as the conditional is written in this form:

if est == 'São Paulo' or 'SP':

So the comparison of if evaluates the literal value 'SP'.

Like any string other than the empty value "" has the return value true, your parole is always assessed as true.

Answer 2

Hello, the problem is happening in the condition of if. It is necessary that you add est == before all possibilities:

if est == 'São Paulo' or est == 'SP' or est == 'sao paulo' or est == 'São paulo': 

Changing this way will enter the if correctly.