I cannot create an iterator class with Ienumerable<T>

Question

I’m creating an iterator class - has support for foreach - implementing the interface IEnumerable<T> package System.Collections.Generic, as in the code below:

public class MyList<T> : IEnumerable<T> {

    private T[] list;

    // Código...

    public IEnumerator<T> GetEnumerator() {
        for (int index = 0; index < this.list.Length; i++) {
            yield return this.list[index];
        }
    }
}

The problem is that the compiler is generating the following error:

error CS0738: "MyList<T>" não implementa membro de interface "IEnumerable.GetEnumerator()
". "MyList<T>.GetEnumerator()" não pode implementar "IEnumerable.GetEnumerator()" porqu não tem o tipo de retorno correspondente de "IEnumerator".

What’s wrong with the code? What am I doing wrong? I have revised the code several times and apparently the implementation is in accordance with the documentation.

Answer 1

No stackoverflow in English has a question similar to yours, follows the free translation of the accepted answer

Like IEnumerable<T> implements IEnumerable you need to implement this interface also in your class, which has the non-generic version of the method GetEnumerator. To avoid conflicts, you can explicitly implement it

IEnumerator IEnumerable.GetEnumerator()
{
    // chama a versão genérica do método
    return this.GetEnumerator();
}

public IEnumerator<T> GetEnumerator()
{
    for (int i = 0; i < Count; i++)
        yield return _array[i];
}