Function to check if one number is divisible by another

Question

The objective of this exercise is to return if the input number is divisible by x or not.

Your program will always receive input: an integer number and an integer number representing x and should print on the screen if the first entry number is divisible by x.

The input will always be two integer numbers.

The output should always be true or false.

Sample Input 0

10 2

Sample Output 0

true

Explanation 0

10 is divided by 2 because by dividing 10 by 2 the rest is 0.

That’s the code I’m using:

function solucao(numero, x) {
// seu código aqui
    return numero % x == 0; {
        console.log(solucao (10,2))
        if (resto == 0) {
          console.log("true");
        } else {
            console.log("false");
        }
    } 
}

Answer 1

The equality operator == checks if your two operands are equal, returning a result boolean, true or false. So no need to test the remnant to print strings with the results.

When a statement return is used in a function body, the execution of that function is stopped and the code after the declaration will not be interpreted. If specified, a given value is returned to the one who called the function. If the expression is omitted, undefined will be returned.

//n= é o numero atestar a divisibilidade.
//d= é o divisor.
function solucao(n, d) {
  return n % d == 0;
}

console.log(solucao(10, 2))

console.log(solucao(7, 3))

Answer 2

I will post here some comments on your code:

// aqui não está usando "x" e também não está passando esse valor , então pode remover
function solucao(numero) {   // <- sem o "x"
    const resto = numero % 2; 
    if (resto == 0) { 
       console.log("true") 
    } else {
       console.log("false")  // <- faltou isso, que é o "else" caso o resto não seja zero
    }
};


solucao(10);
solucao(7);