How to pass a dictionary to the range() function

Question

I was looking at the documentation (docstring) of the range function and came across the following:

Init signature: range(self, /, *args, **kwargs)
Docstring:     
range(stop) -> range object
range(start, stop[, step]) -> range object

My understanding is that the function range() takes both positional arguments (a tuple or list) and keyword arguments (dictionary).

Testing, I managed to do the following:

# passando argumentos da forma padrão:
for i in range(0, 10, 1):
    print(i)

Returns sequence 1 to 10 with step 1.

# passando argumentos como uma lista:
for i in range(*[1, 10, 2]):
    print(i)

Using the * as an "unpacking" indicator, the range resolves and returns an iterable with: 1, 3, 5, 7, 9.

And if I wanted to pass a dictionary, as below?

for i in range(**{'start':0, 'stop':100, 'step':10}):
    print(i)

While executing the above code I take an error:

Typeerror: range() takes no keyword argumentsrangeRange

It’s a docstring error, or you don’t even have a way to pass **kwargs for the range?

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EDIT: version and docstring

Answer 1

This happens because the function range is not implemented directly in Python, but rather in C. In this case, the C function has been developed to accept only the arguments in positional form.

Although, in the case of range, is shown by the documentation the argument names start, stop and step, they cannot be passed through the form named on account of the said limitation.

Of language reference:

Cpython implementation Detail: An implementation may provide built-in functions Whose positional Parameters do not have Names, Even if they are ːnamed' for the purpose of Documentation, and which therefore cannot be supplied by keyword. In Cpython, this is the case for functions implemented in C that use PyArg_ParseTuple() to parse their Arguments.

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This response was based in this question (and answers) soen.