Compare Char matrix and vector

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How do I make, in C, a code that compares whether the line responses of an array are equal to the line of an array? Follows the question:

imagem da pergunta

Follow the code I have:

#include <stdio.h>

int main()
{
    char ma[5][10] = {'a','b','c','d','d','c','b','a','b','b','d','a','d','c','b','a','b','b','d','a',
    'd','d','c','b','a','b','b','d','a','d','b','d','a','d','c','b','a','b','b','d','c','d','d','c',
    'b','a','b','b','d','a'}, letter;
    char gab[10] = {'a','b','c','d','a','b','c','d','b','b'};
    int resultado[10], r, l, soma = 0;
    
    //Corrigindo
    for(r = 0; r < 5; r++){
        for(l = 0; l < 10; l++){
            if(ma[r][l] == gab[l]){
                soma++;
            }
            resultado[r] =  soma;
        }
    }
    
    printf("Resultados\n\n");
    for(r = 0; r < 5; r++){
        printf("Aluno %d: %d\n", r+1, resultado[r]);
    }

    return 0;
}
c

  • This answers your question? Compare a char vector?

  • https://answall.com/questions/247225/como-comparar-vetores-em-c

  • https://answall.com/questions/390538/como-comparar-uma-posi%C3%A7%C3%A3o-da-string-com-um-character-c

  • I believe that in your section "Correcting" you must reset the accumulator soma for each line r otherwise it will not make sense what will store in resultado. for(r = 0; r < 5; r++){ soma = 0; for(l = 0; l < 10; l++){ if(ma[r][l] == gab[l]){ soma++; } resultado[r] = soma; } }

  • It didn’t work. After doing this he reset all the results. I tested tbm before the r FOR and after l. No results.

  • Here https://ideone.com/PDDeaK worked.

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2 answers

0

Note that for each letter of 'ma' corresponding to 'Gab' sum you receive 1. Thus, it makes no sense for the result of 4 and 5 to be 13. It follows excerpt of Cod showing matrix and vector, for comparison:

#include <stdio.h>

int main() { char ma[5][10] = {'a','b','c','d','d','c','b','a','b','b','d','a','d','c','b','a','b','b','d','a', 'd','d','c','b','a','b','b','d','a','d','b','d','a','d','c','b','a','b','b','d','c','d','d','c', 'b','a','b','b','d','a'}; char gab[10] = {'a','b','c','d','a','b','c','d','b','b'}; int result[10], r, l, sum = 0;

//imprimindo matriz
for(r = 0; r < 5; r++){
    for(l = 0; l < 10; l++){
        printf("%c  ",ma[r][l]);
    }
    printf("\n");
}
printf("\n\n");
//imprimindo gabarito
for(l = 0; l < 10; l++){
    printf("%c  ",gab[l]);
}
printf("\n\n");
for(r = 0; r < 5; r++){
    for(l = 0; l < 10; l++){
        if(ma[r][l] == gab[l]){
            soma++;
        }
        resultado[r] =  soma;
    }
}

printf("Resultados\n\n");
for(r = 0; r < 5; r++){
    printf("Aluno %d: %d\n", r+1, resultado[r]);
}

return 0;

}

  • That’s not an answer. If you want to add something to your question, just edit it and add whatever you think is necessary to clarify who will answer.

  • Then was to answer the guy from the previous answer. I did so because the code did not fit here.

0

Apparently your code already does what is requested, I ran this code and it worked perfectly.

#include <stdio.h>

int main() {
    char ma[5][10] = {'a','b','c','d','d','c','b','a','b','b','d','a','d','c','b','a','b','b','d','a', 'd','d','c','b','a','b','b','d','a','d','b','d','a','d','c','b','a','b','b','d','c','d','d','c', 'b','a','b','b','d','a'};
    char gab[10] = {'a','b','c','d','a','b','c','d','b','b'};
    int resultado[10], r, l, soma = 0;
    
    for(r = 0; r < 5; r++){
        for(l = 0; l < 10; l++){
            if(ma[r][l] == gab[l]){
                soma++;
            }
            resultado[r] =  soma;
        }
    }

    printf("Resultados\n\n");
    for(r = 0; r < 5; r++){
        printf("Aluno %d: %d\n", r+1, resultado[r]);
    }

    return 0;
}

  • I managed to resolve with the help of a member of another forum, thanks to all who made their time to help me.

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