Algorithm in C loop of for repeating response

Question

Guys I’m going to college and I got stuck in a list exercise, it’s a C algorithm, could help me

My problem is that I put a number to serve the variable x and it calculates about 4 times properly, the numbers come out different, then the result comes out all the same, until you give the loop 10 times, thanks for the help

#include <stdio.h>

int main() {
  float x, m, e, h, y, n, f, b, l, k, w;
  int s;
  printf(“Digite um valor para o angulo em radiano\ n”);
  scanf("%f", & x);
  w = 0;
  k = 0;
  y = 0;
  h = 1;
  f = 0;
  for (s = 1; s <= 8; s++) {

    b = s % 2;

    /*Colocar o valor positivo e negativo usando o if*/
    if (b == 0) {
      w = w + 2;
      y = pow(x, w);
      y = y * (-1);
    } else {
      w = w + 2;
      y = pow(x, w);
      y = y * 1;
    }

    /*Calculo do fatorial*/
    k = 1;
    f = f + 2;
    m = f;
    for (; m > 0; m = m - 1)
      k = m * k;

    /*resultado final*/
    h = y / k + h;
    printf("%f\n", h);
  }
  return 0;
}

Answer 1

Hello, I noticed that your code has some redundancies, for example equal commands within the if and in Else, unused variables and did not include the mathematical library to use the Pow function, I advise to fix this. I didn’t understand the purpose of your program, but I realized that the repetition of equal results is due to the lack of precision in the decimals, that is, the latest results differ in a quantity less than 10 -6 and so it is not possible to notice that they are different since the float shows up to 6 decimal places, if multiplying the result in Y is remarkable that

#include <stdio.h>
#include <math.h>
int main() {
  double x, m, h, y, f, b, k, w;
  int s;
  printf("Digite um valor para o angulo em radiano\n\t");
  scanf("%lf", &x);
  w = 0;
  k = 0;
  y = 0;
  h = 1;
  f = 0;
  for (s = 1; s <= 8; s++) {

b = s % 2;

/*Colocar o valor positivo e negativo usando o if*/

w = w + 2;
y = pow(x, w);

if (b == 0) {
  y = y * (-1);
}

/*Calculo do fatorial*/
k = 1;
f = f + 2;

for (m=f ; m > 0; m--){
    k = m * k;
}


/*resultado final*/
h = 1000000000*y / k + h;
printf("%lf\n", h);
}return 0;}