Inverting variables (Python)

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1

I know you can do it in other ways, but I’ve done it limited to ifs. I wonder why I’m reversing the results in the last part of the code.

from random import randint
    
pedra, papel, tesoura = "1", "2", "3"
    
print("[1] Pedra\n[2] Papel\n[3] Tesoura")
p = int(input("Pense no que vai jogar: \n"))
d, e, c = "Você perdeu!", "Empate!", "Você ganhou!"
pe, pa, te = "Pedra", "Papel", "Tesoura"
    
if p == 1:
    print("Você jogou:", pa)
elif p == 2:
    print("Você jogou:", pe)
elif p == 3:
    print("Você jogou:", te)
    
pc = randint(1, 3)  
    
if pc == 1:
    print("PC jogou:", pa)
elif pc == 2:
    print("PC jogou:", pe)
elif pc == 3:
    print("PC jogou:", te)
    
if pc == p:
    print(e)
elif pc == 1 and p == 2:
    print(d)
elif pc == 2 and p == 1:
    print(c)
elif pc == 3 and p == 1:
    print(d)
elif pc == 1 and p == 3:
    print(c)
elif pc == 3 and p == 2:
    print(c)
elif pc == 2 and p == 3:
    print(d)
python python-3.x
  • 2

    We speak Stone, Paper and Scissors... You put 1 = paper, 2 = stone, 3 = Scissors. Then you left your code confused. Change the values to 1 = stone, 2 = paper, 3 = scissors and redo the if. It will make it easier for you. The error is in the other ifs and not in the last two.

1 answer

1

elif pc == 1 and p == 2:
    print(c)
elif pc == 2 and p == 1:
    print(d)
elif pc == 3 and p == 1:
    print(c)
elif pc == 1 and p == 3:
    print(d)
elif pc == 3 and p == 2:
    print(d)
elif pc == 2 and p == 3:
    print(c)

The problem was that where the player won, he was imprinted with the varietal that showed him as a loser. Just replace, in the last if, where you have "c" by "d" and vice versa, as shown in the code above.

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