-4
Write the maximum function that takes 2 integers as parameter and returns the largest of them.
example:
>>> maximo(3, 4)
4
>>> maximo(0, -1)
0
3 answers
4
If you cannot use builtin max that returns the largest item in an iterable or larger than two or more arguments.:
>>> max(3, 4)
4
Compare the arguments to decide which one is bigger and return it.
def maior1(n1, n2):
if n1 > n2:
return n1
return n2
def maior2(n1, n2):
return n1 if n1 > n2 else n2
maior3 = lambda n1, n2: n1 if n1 > n2 else n2
print(maior1(4, 8)) #8
print(maior2(32, 2)) #32
print(maior3(687, 8233)) #8233
The three functions maior1(), maior2() and maior3() are equivalent.
maior1()uses a if statementmaior2()uses a conditional expression.maior3()is declared with a lambda expression and uses a conditional expression
-4
def maximo(n1,n2):
if n1 > n2:
print(n1)
elif n2 > n1:
print(n2)
else:
print(f'{n1} é igual a {n2}')
maximo(0,1)
-
2
Note the detail that your function is not returning (read returning) the value as it is prompted, just displaying it.
-
2
Another detail: what if
n1is equal ton2? -
so I added an if and an Elif, I could have added an if and an Else, but if they were equal the largest would be the N2.
-7
Hello! Try that code here:
def mostra_maior(num1, num2):
if num1 > num2:
print(num1)
else:
print(num2)
mostra_maior(4,8)
>>> 8
-
4
And if you do
mostra_maior(8, 4), what the exit will be?
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