program in C to calculate the average , average and quantity of odd numbers

Question

The point is this

:Make a C program that reads from the user an integer vector with n positions in the range [5, 200]. Repeat the value of n until a valid value is entered by user. After reading the n values typed by the user some statistics should be extracted from this vector: a) Print the Vector Average on the screen; b) Print the median of the vector on the screen; c) Print on the screen the number of odd numbers and pairs of the vector.

Note: The real numbers must be printed on the screen with precision of two houses decimal;

Assume that the vector is already typed ordered by the user; The simple arithmetic mean corresponds to , where x corresponds to each element vector with n positions. The calculation of the median of ordered data of samples of size n may be performed as follows: if n is odd, the median shall be the central element . If n is even, the median will be the result of the simple mean between the elements and +1;

I tried to solve but I’m not used to this precise system of typing variables in the C language, here is my code (this very precarious):

   #include <stdio.h>

   int main(){

int comeco =0, fim =0;
int v[1000];
int tam = fim - comeco;
int m = 0,md, impar = 0;
float media, mediana;

do{

printf("Digite um numero no intervalo de 5 a 200");
scanf("%i %i", &comeco, &fim);
getchar();

}while(comeco < 5 || fim > 200);

int i = 0;

for (int j = comeco; j < fim; j++) {
    v[i] = j;
    i+=1;
    if(v[i] % 2 != 0){
        impar += 1;
        }
}
for (int me = 0; me < tam; me++) {

    m += v[me];
}
media = (float)m/(float)tam;
printf("%.2f\n", media);
printf("%i impar \n", impar );

if(tam % 2 == 0){
    md = (tam/2);
    mediana = ((float)v[md]+ (float)v[md-1])/2;
}else{
    md=(tam/2);
    mediana=(float)v[md];
}
printf("%.2f", mediana);

}