Replace inverted bars with single bars - image URL

Question

I am trying to remove the backslashes to open the image URL, I found a way to replace, but part of my string was lost:

function formatURL( $url )
{    
    echo $url."<br />";

    $url = str_replace('\\', '/', $url);

    echo $url."<br />";
}

echo "http://10.0.0.1/fotoou/aplic\1\7\1\3\9\8\1\\1893171_1.jpg<br />";

$url = formatURL("http://10.0.0.1/fotoou/aplic\1\7\1\3\9\8\1\\1893171_1.jpg");

echo $url;

The strange thing is that my return is:

http://10.0.0.1/fotoou/aplic\9\8\1893171_1.jpg
http://10.0.0.1/fotoou/aplic\9\8\1893171_1.jpg
http://10.0.0.1/fotoou/aplic/9/8/1893171_1.jpg

Part of the lost string:

\1\7\1\3\

Answer 1

This is because, the way you declared the string, you should have put two backslashes for each bar you want to print. It’s called "escaping the bars".

See about this in "Escape Sequences" in the [PHP Handbook].(http://php.net/manual/en/language.types.string.php)

In the case of double quotes declared strings (as in your example), using this backslash alone causes the PHP recognize that you are wanting to insert a special character.

In case, you have two options:

1. You can simply replace the aspas duplas for aspas simples
2. Or you put two bars instead of two bars (if you’re going to use the Apas doubles ")

Possible changes to your code

Example 1 (String with double quotes):

$url = formatURL("http://10.0.0.1/fotoou/aplic\\1\\7\\1\\3\\9\\8\\1\\1893171_1.jpg");

Example 2 (String with single quotes):

$url = formatURL('http://10.0.0.1/fotoou/aplic\1\7\1\3\9\8\1\\1893171_1.jpg');