Return repeated in action on the flutter login screen

Question

  bool _login;
  Future<bool> login(String email, String senha) async {
    var response = await http.get("http://192.168.0.116:5001/usuarios/login/$email/$senha");
    if(response.statusCode == 200) {
      return _login = true;
    } else {
      return _login = false;
    } 
  }

Knob:

    RaisedButton(
      shape: RoundedRectangleBorder(
        borderRadius: BorderRadius.circular(12),
      ),
      color: HotelAppTheme.buildLightTheme().primaryColor,
      onPressed: () {
        logar();
        _login == true ? print('s') : print('n');
 
      },
      child: Text('Entrar', style: TextStyle(
        fontSize: SizeConfig.of(context).dynamicScaleSize(size: 18),
        color: Colors.white
        ),
      ),
    );

If I enter a valid email and password and click on the button, I have as return "s", so far everything working as expected, however, if I change and put an invalid email or password, and click the button again, the return is still "s", but if I click the button again, the return changes to "n" as expected. Why in the first action it does not update?

I thank anyone who can help me.

Answer 1

Make the function onPressed also asynchronous button, and wait for completion of login function:

[...]
onPressed: () async {
                    await logar();
                    _login == true ? print('s') : print('n');
             
                  }
[...]

How did you not use the await, the function onPressed will not wait for the return of get, so using the variable value _login wrong.

For more learning about asynchronous calls and the keyword await, try it this guide (in English), or search for other questions here on the same network.