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I have two files: one that is the base and the other the 'main' that makes generate the service in windows; However, when I try to start the service, the path of the executable is like another
Does anyone know how I do this modification using pywin32?
that’s the basis:
import socket
import win32serviceutil
import servicemanager
import win32event
import win32service
import logging
import sys
logging.basicConfig(filename="SMWinservice.py", level=logging.DEBUG)
class SMWinservice(win32serviceutil.ServiceFramework):
_svc_name_ = 'Extrator Service'
_svc_display_name_ = 'Extrator Service'
_svc_description_ = 'Python Service Description'
@classmethod
def parse_command_line(cls):
win32serviceutil.HandleCommandLine(cls)
def __init__(self, args):
win32serviceutil.ServiceFramework.__init__(self, args)
self.hWaitStop = win32event.CreateEvent(None, 0, 0, None)
socket.setdefaulttimeout(60)
def SvcStop(self):
self.stop()
self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
win32event.SetEvent(self.hWaitStop)
def SvcDoRun(self):
self.start()
servicemanager.LogMsg(servicemanager.EVENTLOG_INFORMATION_TYPE,
servicemanager.PYS_SERVICE_STARTED,
(self._svc_name_, ''))
self.main()
def start(self):
pass
def stop(self):
pass
def main(self):
pass
# entry point of the module: copy and paste into the new module
# ensuring you are calling the "parse_command_line" of the new created class
if __name__ == '__main__':
SMWinservice.parse_command_line()
if len(sys.argv) == 1:
servicemanager.Initialize()
servicemanager.PrepareToHostSingle(SMWinservice)
this is the main:
import time
from datetime import datetime
from pathlib import Path
from SMWinservice import SMWinservice
import psutil
class Extrator(SMWinservice):
_svc_name_ = "Extrator"
_svc_display_name_ = "Extrator"
_svc_description_ = "Extrator de dados TARGIT"
def start(self):
self.isrunning = True
def stop(self):
self.isrunning = False
def main(self):
Extrator(SMWinservice)
if __name__ == '__main__':
Extrator.parse_command_line()