How to get the host name in Urls?

Question

How to get the name of host of a URL like Mega, 4shared among others with PHP?

In case you would like to know taking this URL as an example:

https://mega.co.nz/#! 4090kJrY! Lzizbgsoo_gg1slnykzlhsuthac9oaprg3--0gD92Y

How can I get from this URL only the word MEGA discarding all the rest?

I found this type of code on the Internet which picks up the name of the host only it does not do what I want because it leaves the www and the domain I just want to leave the host name.

$host = $_SERVER['HTTP_HOST'];
echo $host;

Answer 1

Maybe what you want is this:

<?php
$url = 'https://mega.co.nz/#!4090kJrY!LZiZBgsOo_Gg1sLnykZLHsUThAC9oaPRG3---0gD92Y';
$array_url = parse_url($url);
print_r($array_url);
echo parse_url($url, PHP_URL_HOST) . "\n"; //pega o HOST
echo $array_url['host'] . "\n"; //aqui pega só o HOST também.
$dominio = explode(".", parse_url($url, PHP_URL_HOST));
echo $dominio[0];
?>

Behold working in the ideone. And in the repl it.. Also put on the Github for future reference.

Job documentation.

Answer 2

You can get this value by manipulating HTML, see:

$contextOptions = array(
    "ssl"=>array(
        "verify_peer" => false,
        "verify_peer_name" => false,
    ),
); 

$url = file_get_contents("https://mega.co.nz/#!4090kJrY!LZiZBgsOo_Gg1sLnykZLHsUThAC9oaPRG3---0gD92Y", false, stream_context_create($contextOptions));

$dom = new DOMDocument();
$dom->loadHTML($url);

$title = $dom->getElementsByTagName('title');

print($title->item(0)->nodeValue . "\n"); // MEGA

Demo