I can’t get the None result out of this code

Question

I’m trying to pull this one out None, I’ve already put else, I’ve already put add2 and then I defined add = add2 but I haven’t been able to get it out.

How does it look:

Which fruit do you want to add to the list? strawberry

Want to add more fruit? maybe

Please type yes or no:

None (and the text box to type)

(same problem in both ifs)

frutas = []
novafruta = input('Qual fruta você quer adicionar à lista? ')
frutas.append(novafruta)
add = input('Quer adicionar mais fruta? ')

if add != 'sim' or add != 'não':
    add = input(print('Por favor *digite sim ou não: '))
    
while add == 'sim':
    frutas.append(input('Qual fruta você quer adicionar à lista? '))
    add = input('Quer adicionar mais fruta? ')
    if add != 'sim' or add != 'não':
        add = input(print('Por favor digite sim ou não: '))

Answer 1

Logic is very complicated and redundant. I would even change a little the way of responding to the user to simplify the code, but I don’t know if you can so I’ll keep it that way.

The biggest reason for the mistake is that you have a input() without the need to encapsulate the print(). This makes no sense and makes logic flawed because one only has a chance to make a mistake, then problems. So you have to take that out, but you have to fix all the rest of the logic.

frutas = []
add = 'sim'
while True:
    if add == 'sim':
        frutas.append(input('Qual fruta você quer adicionar à lista? '))
    add = input('Quer adicionar mais fruta? ')
    if add == 'não':
        break
    if add != 'sim' and add != 'não':
        add = print('Por favor digite sim ou não: ')
print(frutas)

Behold working in the ideone. And in the repl it.. Also put on the Github for future reference.