How to delimit the columns of a matrix in Julia

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I have a Matrix 4:3 and would like to catch only 2:3.

Is it possible to delimited using the Delimitedfiles command? How should I use?

Q = convert(Matrix, ACT[2:3]) #Gostaria de omitir o 2:3
  • Hello Raquel. Why not create a function that returns only the rows and columns you want from this matrix? For example, in a hypothetical algorithm, we have m = [[1,2,3,4],[5,6,7,8],[9,10,11,12],[13,14,15,16]] running through the matrix in a loop for for i in matrix 
 for j in matrix 
 if (j != row AND J != col ) 
 print(matrix[i][j] if row = 0 and col = 0 temos [[6,7,8],[10,11,12],[14,15,16];

  • Hi Felipe, thank you so much for the help. I did exactly how you posted and it didn’t work, it appeared this: invalid iteration specification. I don’t know if at the time I tried to put my data did something wrong, because the "for" you posted makes all the sense rsrsrs

  • You can edit the question and put an example of Matrix 4:3 and what would 2:3 look like you need on output? Maybe, make it easy to answer :-)

  • Hi Gomeiro, thanks for the suggestion. I have a dataframe extracted from a . CSV with 4x3. I would like to view only the numbers that are on this dataframe. Way out I need. 87 0 0 11

  • Let’s see if I understand...Dataframe has 4 columns and 3 rows and you need to extract all elements that are in the first 2 columns (and 3 rows)? That’s it?

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