-3
Problem 3:
Make a function that receives, as a parameter, a vector with ten integers and return them ordered in increasing form.
The code I’m using:
#include <stdio.h>
int main(){
int i, troca,j,vetor[10], ordenado[10];
for (i=0;i<10;i++){
printf("Informe o numero %d de um vetor de 10 numeros",i+1);
scanf("%d", &vetor[i]);
}
for (i=0;i<10;i++){
for(j=i+1;j<10;j++){
if(vetor[i] > vetor[j]){
troca = vetor[i];
vetor[i] = vetor[j];
vetor[j] = troca;
}
}
}
for (i=0;i<10;i++){
printf("Posição %d do vetor %d \n",i+1,vetor[i]);
}
}
The code with the function:
#include <stdio.h>
int converte (int *vetor[10]){
int i,j,troca;
for (i=0;i<10;i++){
for(j=i+1;j<10;j++){
if(vetor[i] > vetor[j]){
troca = vetor[i];
vetor[i] = vetor[j];
vetor[j] = troca;
}
}
}
for (i=0;i<10;i++){
printf("Posição %d do vetor %d \n",i+1,vetor[i]);
}
int main(){
int i, troca,j,vetor[10], ordenado[10];
for (i=0;i<10;i++){
printf("Informe o numero %d de um vetor de 10 numeros",i+1);
scanf("%d", &vetor[i]);
}
for (i=0;i<10;i++){
for(j=i+1;j<10;j++){
if(vetor[i] > vetor[j]){
troca = vetor[i];
vetor[i] = vetor[j];
vetor[j] = troca;
}
}
}
for (i=0;i<10;i++){
printf("Posição %d do vetor %d \n",i+1,vetor[i]);
}
}
Error:
C:\Users\Usuario\Desktop\Exercicios alp2\testes1.cpp In function 'int converte(int**)':
7 20 C:\Users\Usuario\Desktop\Exercicios alp2\testes1.cpp [Error] invalid conversion from 'int*' to 'int' [-fpermissive]
9 14 C:\Users\Usuario\Desktop\Exercicios alp2\testes1.cpp [Error] invalid conversion from 'int' to 'int*' [-fpermissive]
18 11 C:\Users\Usuario\Desktop\Exercicios alp2\testes1.cpp [Error] a function-definition is not allowed here before '{' token
38 1 C:\Users\Usuario\Desktop\Exercicios alp2\testes1.cpp [Error] expected '}' at end of input
But its function
converte
should receive an array of pointers for int or should it be an int array? Its version with function should invoke the function.– anonimo