Ordering result

Question

Good evening, I need help making a word sorting of that code.

texto = '''amar e viver, Amar é sonhar, sonhar é viver, viver é curtir, curtir é amar'''

def converte_texto(texto):
    pontuacao = ['.',',',':',';','!','?','"','(', ')']
    novo_texto = ''.join(c for c in texto if c not in pontuacao).upper()
    lista = novo_texto.split()
    return lista

def palavras(texto):
    palavras = converte_texto(texto)
    contagem = dict()

    for palavra in palavras : 
        contagem[palavra] = contagem.get(palavra, 0) + 1

    return contagem

print(palavras(texto))

That is the result:

{'AMAR': 3, 'E': 1, 'VIVER': 3, 'É': 4, 'SONHAR': 2, 'CURTIR': 2}

I’m trying to get him out in an orderly descending fashion, but I’m having a hard time.

Answer 1

You can use the method sorted, specifying the key to be used in the comparison. In this case:

def palavras(texto):
    palavras = converte_texto(texto)
    contagem = dict()

    for palavra in palavras : 
        contagem[palavra] = contagem.get(palavra, 0) + 1

    return return dict(sorted(contagem.items(), key=lambda x: x[1], reverse=True))

Output:

{'É': 4, 'AMAR': 3, 'VIVER': 3, 'SONHAR': 2, 'CURTIR': 2, 'E': 1}

Answer 2

To sort a dictionary in Python is very simple since the language has its own method for this that works with both dictionaries, such as lists and tuples.

The syntax is sorted(object, key, reverse), where, in your case, Object is the dictionary itself, key is the form of organisation and reverse is a boolean to say whether you want to invert the list or not. It is optional and leaving blank will not invert the answer. The key is also optional and if not informed will make an alphabetical ordering of your keys.

As your case needs sorting by values we will need to increment with another function: items().

So just add the following line in your code and then return this variable further down. The lambda function here works as the sorter and is basically an unnamed function. I won’t explain it here, because it’s not the scope of the question, but if you want to know more about it, here’s a good explanation.

ordenado = sorted(orders.items(), key=lambda x: x[1], reverse=True)
return ordenado

Note that as you want an ordering from the highest to the lowest, I gave the value true for the variable reverse. At the end your code is:

texto = '''amar e viver, Amar é sonhar, sonhar é viver, viver é curtir, curtir é amar'''

def converte_texto(texto):
  pontuacao = ['.',',',':',';','!','?','"','(', ')']
  novo_texto = ''.join(c for c in texto if c not in pontuacao).upper()
  lista = novo_texto.split()
  return lista

def palavras(texto):
  palavras = converte_texto(texto)
  contagem = dict()

  for palavra in palavras : 
      contagem[palavra] = contagem.get(palavra, 0) + 1

  ordenado = sorted(contagem.items(), key=lambda x: x[1], reverse=True)

  return ordenado

print(palavras(texto))