Simple question from PHP

Question

I have this line in a code to connect to the database, but the following error appears:

Code

$con=mysql_connect("localhost","root","");

Error

Fatal error: Uncaught Error: Call to Undefined Function mysql_connect() in C: xampp htdocs login bancoDespesas.php:8 Stack trace: #0 {main} thrown in C: xampp htdocs login bancoDespesas.php on line 8

How can I solve?

Answer 1

Apparently missing parameters for connection. Below is the method I do.

<?php 

    $DATABASE_HOST = 'localhost';
    $DATABASE_USER = 'root';
    $DATABASE_PASS = '';
    $DATABASE_NAME = 'nome_do_banco';

    $con = mysqli_connect($DATABASE_HOST, $DATABASE_USER, $DATABASE_PASS, $DATABASE_NAME);
    if ( mysqli_connect_errno() ) {
        header('HTTP/1.1 500 Internal Server Error');
        header('Content-Type: application/json');
        die(json_encode(array('message' => 'Falha ao Conectar ao MySQL: ' . mysqli_connect_error(), 'code' => 599)));
        exit('Falha ao Conectar ao MySQL: ' . mysqli_connect_error());
    }
?>

Here is also an example of the site itself php.

<?php
$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
    die('Could not connect: ' . mysql_error());
}
echo 'Connected successfully';
mysql_close($link);
?>

But I believe that this method only works in php5 if you are using php7 the first and best choice. I hope I have helped.