Find at least one result within a mongoDB array

Question

I would like to return the user posts if they have at least one of the tags similar to the post

For example:

• User tags ["react","c#","node"]
• Post tags ["c#","sqlserver","asp.net"]

How the user has the tag C# and the post also, I would like to include it in the result of the consultation, through the documentation I could only get to the part where I return if the array user.tags is entirely contained in posts.tags

   const user = await Users.findById(user_id);
    if (!user) {
        return res.status(401).send('Usuário inválido');
    }
    const posts = await Posts.find({ tags: { $all: user.tags } });

https://docs.mongodb.com/manual/tutorial/project-fields-from-query-results/

Answer 1

According to the documentation to achieve the desired result just change the operator $all for $in

A possible solution would be:

const posts = await Posts.find({ tags: { $in: user.tags } });