Prevent script from following symbolic links

Question

With the script below, a search is carried out for all the accommodations in the indicated directory in order to obtain the email addresses associated with each accommodation:

#!/bin/bash

# Scan All available email account addresses
# for homedir under the provided path
# 2014-12-19 Salustiano Silva

# Control :: Provided directory supplied ?
if [ -z "$1" ]; then
    echo "É preciso passar como parâmetro o caminho completo para a diretoria 'home'!"
    exit
fi

HOMEDIR="$1"

# Control :: Provided directory exists ?
if [ ! -d "$HOMEDIR" ]; then
    echo "A diretoria $HOMEDIR não foi localizada, verifique os dados fornecidos!"
    exit    
fi


HOMEDIR="$1"
CPANELUSERS=`ls -1A /var/cpanel/users/`

count=1
for x in `echo -n "$CPANELUSERS"`;do
  wiersz=`grep -i ^dns /var/cpanel/users/"$x" |cut -d= -f2`
  DOMAIN[$count]=$wiersz
  count=$[$count+1]
  echo "Login:        `echo "$x"`"


    for i in `echo "${DOMAIN[@]}" | sed  's/ /\n/g'`;do
      for n in ` ls -A "$HOMEDIR""$x"/mail/"$i"/ 2>/dev/null`;do

           if   [ "$n" == "cur" ];then echo "$n" > /dev/null
           elif [ "$n" == "new" ];then echo "$n" > /dev/null
           elif [ "$n" == "tmp" ];then echo "$n" > /dev/null
           elif [ "$n" == "" ];then echo "$n" > /dev/null
           else
           echo  "$n"@"$i"
           fi
      done
    done
    echo;echo;
done

Example of use:

./getMails /home/ > lista.txt

Output in the file lista.txt:

Login:        example
[email protected]
[email protected]
[email protected]
[email protected]
[email protected]
[email protected]


Login:        test
[email protected]
[email protected]
[email protected]
[email protected]
[email protected]
[email protected]

Question

How can I prevent the script from following symbolic links to other locations by only searching with "regular directories" ?

Answer 1

Instead of doing ls in $HOMEDIR, use the command find, in this way:

find $HOMEDIR -maxdepth 1 ! -type l

The -maxdepth 1 searches only at a directory tree level (similar to ls) the ! -type l search only files that are not symbolic links

More about the ls at this link: http://rberaldo.com.br/curso-shell-script-comandos-basicos-linux/

Answer 2

You can use ls -l and remove the lines it contains "->".

Whirling ls -lA, you will get something like this:

-rw-------    1 root     root           576 Jan 21 16:22 .ash_history           
lrwxrwxrwx    1 root     root             9 Jan 21 16:18 dos -> /root/dos       
-rw-r--r--    1 root     root           242 Jan 21 16:18 hello.c   

Then you can only get the filenames from 58° character using cut -c 58-:

$ ls -lA | cut -c 58-

.ash_history                                                                    
dos -> /root/dos                                                                
hello.c

And from this result you can extract only what you don’t have ">" with grep -v '>' :

$ ls -lA | cut -c 58- |grep -v '>'  

.ash_history                                                                    
hello.c   

In short: change your ls -A for ls -lA | cut -c 58- |grep -v '>'

NOTE: This option will include a blank line along with the result, but your code already has a treatment for this.

Answer 3

Does not process ls.

The test [ -L … ] identifies symbolic links.

for i in "${DOMAIN[@]}"; do
  for f in "$HOMEDIR$x/mail/$i"/* "$HOMEDIR$x/mail/$i"/.*; do
    n="${f%%*/}"  # o nome sem o diretório
    case "$n" in
      .|..|cur|new|tmp) continue;; # arquivos não interessantes
    esac
    if [ -L "$n" ]; then continue; fi  # ligação simbólica
    echo  "$n"@"$i"
  done
done