Isset in PHP ternary?

Question

I have the following examples of condition in ternario, in the first example it works correctly, it returns me the data and if it is empty returns null, however in the second example I think would be correct, it returns me the data correctly but does not return me null when empty.

Example 1:

$data->mala_grande = ($t->malagrande) ? $t->malagrande :null;  

Example 2

$data->mala_grande = (isset($t->malagrande)) ? $t->malagrande :null;

• Would you be doing something wrong using this first example without the isset?
• I can continue on this option?
• The first option Without putting the isset she would be playing the same role automatically?

Answer 1

isset() is not used to test if a value is empty. The function is to check whether the variable is set or not.

The empty() is to test whether a variable is "empty", and has the same property as the isset of not generating a Warning if the variable is missing:

$data->mala_grande = ! empty($t->malagrande) ? $t->malagrande : null;
//                   ^ o ! inverte a lógica do teste                      

Or else

$data->mala_grande = empty($t->malagrande) ? null : $t->malagrande;

In the first case we are using the not Empty (! empty()), that is to say:

• "if nay for empty returns t->malagrande, otherwise null.

In the second case:

• "if empty returns null, otherwise, t->malagrande.

They result in the same thing, written in different ways.

Handbook:

https://www.php.net/manual/en/function.empty.php