Error in my C Program

Question

When I type 0 it does not inform as the program should: "Incorrect input. Enter an integer value".

#include <stdio.h>

void LimpaBuffer(void)
{  
    int valorLido; /* valorLido deve ser int */
    do {
        valorLido = getchar();
       } while((valorLido = '\n') && (valorLido !=EOF));
}
int main(void)
{
    int umInt, outroInt, nValoresLidos;
    printf("Digite um valor inteiro");
    nValoresLidos = scanf("%d", &umInt);
    while(nValoresLidos == 0) { //Nenhum inteiro for lido
        LimpaBuffer();
        printf("Entrada incorreta. Digite um valor inteiro");
        nValoresLidos = scanf("%d", &umInt);
    }
    printf("Digite outro valor inteiro");
    nValoresLidos = scanf("%d", &outroInt);
    while (nValoresLidos == 0) {
        LimpaBuffer();
        printf("Entrada incorreta. Digite um valor inteiro");
        nValoresLidos = scanf("%d", &outroInt);

    }
    printf("\n%d + %d = %d", umInt, outroInt, umInt + outroInt);
    return 0;
}

Answer 1

This program is correct. What is wrong is the way AP thinks.

The while(nValoresLidos == 0) that is to say:

As the scanf not read, in this case, a %d gives reading error!

For example if you type:

Digite um valor inteiro
0
Digite outro um valor inteiro
1

0 + 1 = 1

That is absolutely correct.

In this case '0' is not a wrong form in input.

---

[Edit]

In addition this line lacks a !:

} while((valorLido = '\n') && (valorLido !=EOF));

should be :

} while((valorLido != '\n') && (valorLido !=EOF));

That way it’ll work properly.

Answer 2

In the loop while you are checking the nValoresLidos, but the scanf does not assign the value to nValoresLidos and yes to outroInt.

Do so:

scanf("%d", &outroInt);
nValoresLidos = outroInt;