Turning binary into a Python chart

Question

Good evening I have a message that I turned into binary and wanted to make a graph from the following patterns ami pseudoternary, where if the binary digit 1 the frequency is 0 and if the binary digit is 0 it is alternating the frequency between positive(1) and negative(-1):

I’m using the Tkinter and matplotlib libraries but I’m open to other options. My attempt was to go through each digit of the binary string and compare whether it is 1 or 0, but I’m having difficulty even passing it to the graph.

for i in binario.get():
    if i==1:
        #fazer algo no gráfico
    if i==0:
        #fazer algo no gráfico começando positivo e variar

Answer 1

I don’t know if you have to apply some rule (you didn’t specify in the question and I honestly don’t know what this pattern is about), but basically, if you want to make the image graph, just use the code below:

import matplotlib.pyplot as plt
binarios = [0,1,0,0,1,0]
graph = []
anterior = 0 # verifica se o numero anterior é 0, para pular para 1
index = [0]
i = 1 # precisa iniciar em 1 pq já temos a primeira posição no array de index
for binario in binarios:
    if(not binario): # not 0 -> true --> verifica se o binário é ZERO
        if(anterior == 0):
            graph.extend((1,1))
            anterior = 1
        else:
            graph.extend((-1,-1))
            anterior = 0
    else: # binário é HUM
        graph.extend((0,0))
    index.extend((i,i)) if i != len(binarios) else index.append(i)
    i += 1

plt.plot(index, graph)