I need help creating two tables with PHP decision structure

Question

Create a PHP application that checks word by word of the array below if the total letters is odd or even.

To show the result. assemble a basic HTML page with two tables: One with total odd letters words and the other with total even letters, followed by total letters.

$valores = [ 'estudar', 'educação', 'esforço', 'persistência',
             'dedicação', 'crescimento', 'evolução', 'sabedoria',
             'trabalho', 'entusiasmo', 'alegria', 'vitoria',
             'sucesso', 'profissão', 'conhecimento', 'vida' ];

Answer 1

The first step is to get the word size with the function mb_strlen, done this check whether the word size returns or not the rest of the division($tamanho % 2 == 0).

Now define an array with the following structure:

$resultado = array('impares' => '', 'total_impares' => 0, 'pares' => '', 'total_pares' => 0);

If the rest of the division is zero then it is even, add that word in the key $resultado['pares'] and increment the `$result['total_pairs'] pair counter, if the rest is a do the same process only this time in odd.

With formatted array, make two foreach() in the tables.

_{Note: another way to calculate the total would be to use Count in odd/pair keys and assign the value in total_impar/par after the foreach which makes the 'separation'}

Answer 2

Although this is an exercise in logic which, up to the present moment, apparently had no effort on the part of the author demonstrated, I would like to leave my contribution anyway.

The solution is so simple that, apart from the input array, it is solved with only two lines:

$words = [ 'estudar', 'educação', 'esforço', 'persistência',
           'dedicação', 'crescimento', 'evolução', 'sabedoria',
           'trabalho', 'entusiasmo', 'alegria', 'vitoria',
           'sucesso', 'profissão', 'conhecimento', 'vida' ];

$odd = array_filter( $words, function( $word ) { return ( strlen( $word ) % 2 == 0 ); } );

$even = array_diff( $words, $odd );

The arrays $Odd and $Even resulting contains respectively:

array (size=8)
  1 => string 'educação' (length=10)
  2 => string 'esforço' (length=8)
  6 => string 'evolução' (length=10)
  8 => string 'trabalho' (length=8)
  9 => string 'entusiasmo' (length=10)
  13 => string 'profissão' (length=10)
  14 => string 'conhecimento' (length=12)
  15 => string 'vida' (length=4)

array (size=8)
  0 => string 'estudar' (length=7)
  3 => string 'persistência' (length=13)
  4 => string 'dedicação' (length=11)
  5 => string 'crescimento' (length=11)
  7 => string 'sabedoria' (length=9)
  10 => string 'alegria' (length=7)
  11 => string 'vitoria' (length=7)
  12 => string 'sucesso' (length=7)

Unlike friend’s @lost statement, use mb_strlen(), in this case, it results in false-positive because it causes the accents of the words to be considered as additional lengths.

Recommended readings:

• strlen()
• mb_strlen()
• array_filter()
• array_diff()