How to solve a depreciated each() problem?

Question

My code

elseif (is_array($image)) {
        list($key, $width) = each($image);
        list($key, $height) = each($image); 

        $image = imagecreatetruecolor($width, $height);

    }

This excerpt is appearing a Notice de each depreciado. How to solve?

Answer 1

It’s not necessary foreach to perform an operation so simple which can be written, if image is an array of 2 values (probably more, and probably used getimagesize), if you have this:

array(7) {
   [0]=> int(2048) 
   [1]=> int(852) 
   [2]=> int(2) 
   [3]=> string(25) "width="2048" height="852"" 
   ["bits"]=> int(8) 
   ["channels"]=> int(3) 
   ["mime"]=> string(10) "image/jpeg"
}

Just set directly:

$width = $image[0]; //0 é o indice da largura
$height = $image[1]; //1 é o indice da largura

$image = imagecreatetruecolor($width, $height);

An extra note, as I have already commented in another publication:

... «depreciated» is the wrong translation and this being misused and confused with the correct word, «depreciated» in English is «depreciated» and not «deprecated». The word «deprecated» that would be correct to refer to this would be translated as «obsolete», «disapproved», «censured». In the case of use here the best with certainty is «obsolete». Summarizing «depreciated» and «depreciated» has nothing to do with it

Answer 2

I resolved

foreach($image as $key=>$v){
            ($key == 0) ? $width = $v : $height = $v;
        }
        $image = imagecreatetruecolor($width, $height);