Read files in python

Question

good... I have a file with the following things :

if
else
(
)
'
"
print

and the following code :

arq = open('system/commands.txt','r')
arquivo = arq.readlines()
for l in range(0,7):
    print(arquivo[l])

palavra = input('Digite a palavra : ')

if palavra == arquivo[l]:
    print('certo !')

and wanted to know how I do when I type the word that is written in the file it appears the print('right'), in case the above command is not working and wanted to know why !

the command goes to the input part after nothing happens

Answer 1

The problem is related to your variable l; It is defined by for:

for l in range(0,7):
    print(arquivo[l])

When this for executes, the variable l increasing 0 to 6 and the print will print the 7 lines of the file on the screen. Then the variable l used in the for will be with the last value she assumed, that is to say, 6.

Continuing the program, further down you make a comparison:

if palavra == arquivo[l]:

This line is comparing the typed word with the seventh word of the list arquivo, for the value of l is 6, which is the value left over in this variable at the end of the for above;

That is to say, arquivo[l] is equivalent to arquivo[6] (for the value of l at this point is 6) what is a reference to the word "print".

If you type the word print, will receive the message certo; if you type anything else you will not receive any message.